document.write( "Question 1176577: Find the standard form of the equation of the hyperbola with the given characteristics.\r
\n" ); document.write( "\n" ); document.write( "Vertices: (0, ±9); asymptotes: y = ±(3)x
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Algebra.Com's Answer #803726 by MathLover1(20850)\"\" \"About 
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Find the standard form of the equation of the hyperbola with the given characteristics.\r
\n" ); document.write( "\n" ); document.write( "Vertices: (\"0\", ±\"9\"); asymptotes: \"y+\"= ±\"3x\"\r
\n" ); document.write( "\n" ); document.write( "There are two standard forms:\r
\n" ); document.write( "\n" ); document.write( " 1. \"%28x-h%29%5E2%2Fa%5E2-%28y-k%29%5E2%2Fb%5E2=1\"\r
\n" ); document.write( "\n" ); document.write( " 2. \"%28y-k%29%5E2%2Fa%5E2-%28x-h%29%5E2%2Fb%5E2=1\"\r
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\n" ); document.write( "\n" ); document.write( "The point-slope form for the equations of the asymptotes is:\r
\n" ); document.write( "\n" ); document.write( "\"y\"= ±\"+m%28x-h%29%2Bk\"\r
\n" ); document.write( "\n" ); document.write( "Therefore, the equation, \"y+\"}= ±\"3x\" tell us that \"h=0\" and \"k=0\"
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\n" ); document.write( " The center is the point (\"0\",\"0\").\r
\n" ); document.write( "\n" ); document.write( "the vertices given to be, (\"0\", ±\"9\"), tells us that the hyperbola is the \"vertical\" transverse type with the equation in item 2\r
\n" ); document.write( "\n" ); document.write( "\"%28y-k%29%5E2%2Fa%5E2-%28x-h%29%5E2%2Fb%5E2=1\"...substitute \"h\" and \"k\"\r
\n" ); document.write( "\n" ); document.write( "\"%28y-0%29%5E2%2Fa%5E2-%28x-0%29%5E2%2Fb%5E2=1\"\r
\n" ); document.write( "\n" ); document.write( "\"y%5E2%2Fa%5E2-x%5E2%2Fb%5E2=1\"\r
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\n" ); document.write( "\n" ); document.write( "The point (\"0\", \"9\") allows us to discover the value of \"\"a\"\":\r
\n" ); document.write( "\n" ); document.write( "\"9%5E2%2Fa%5E2-0%5E2%2Fb%5E2=1\"\r
\n" ); document.write( "\n" ); document.write( "\"81%2Fa%5E2=1\"\r
\n" ); document.write( "\n" ); document.write( "\"a%5E2=81\"\r
\n" ); document.write( "\n" ); document.write( "\"a=9\"\r
\n" ); document.write( "\n" ); document.write( "the asymptotes allows us to discover the value of \"\"b\"\": \r
\n" ); document.write( "\n" ); document.write( "\"y=3x\", so \"b=3\"\r
\n" ); document.write( "\n" ); document.write( "Substitute the value of \"\"a\"\" and “\"b\"” into equation:\r
\n" ); document.write( "\n" ); document.write( "\"y%5E2%2F9%5E2-x%5E2%2F3%5E2=1\"\r
\n" ); document.write( "\n" ); document.write( "and your equation in standard form is: \r
\n" ); document.write( "\n" ); document.write( "\"y%5E2%2F81-x%5E2%2F9=1\"\r
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