document.write( "Question 1176562: A random sample of 8 observations was drawn from a normal population. The sample mean and
\n" ); document.write( "sample standard deviation are X = 40 and s = 10.
\n" ); document.write( "a) Estimate the population mean with 95% confidence.
\n" ); document.write( "b) Repeat part (a) assuming that you know that the population standard deviation is σ = 10.
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Algebra.Com's Answer #803708 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "Part (a)\r
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\n" ); document.write( "\n" ); document.write( "The sample size is n = 8 and we don't know sigma, which is the population standard deviation. Instead, we have the sample standard deviation value s = 10. This sample statistic estimates the population parameter.\r
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\n" ); document.write( "\n" ); document.write( "Because n > 30 is not true, and we don't know sigma, we must use the T distribution.\r
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\n" ); document.write( "\n" ); document.write( "We have n-1 = 8-1 = 7 degrees of freedom. \r
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\n" ); document.write( "\n" ); document.write( "Use a T table such as this one
\n" ); document.write( "https://www.sjsu.edu/faculty/gerstman/StatPrimer/t-table.pdf
\n" ); document.write( "At the bottom of the table it shows the various confidence levels. Locate the 95% confidence level column. \r
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\n" ); document.write( "\n" ); document.write( "Then mark the df = 7 row
\n" ); document.write( "This is what you should have
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\n" ); document.write( "We can see the value 2.365 is at the intersection of the row and column we highlighted.\r
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\n" ); document.write( "\n" ); document.write( "The t critical value is roughly t = 2.365\r
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\n" ); document.write( "\n" ); document.write( "Let's compute the lower bound L
\n" ); document.write( "L = xbar - t*s/sqrt(n)
\n" ); document.write( "L = 40 - 2.365*10/sqrt(8)
\n" ); document.write( "L = 40 - 8.362
\n" ); document.write( "L = 31.638
\n" ); document.write( "L = 31.64\r
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\n" ); document.write( "\n" ); document.write( "Now the upper bound U
\n" ); document.write( "U = xbar + t*s/sqrt(n)
\n" ); document.write( "U = 40 + 2.365*10/sqrt(8)
\n" ); document.write( "U = 40 + 8.362
\n" ); document.write( "U = 48.362
\n" ); document.write( "U = 48.36\r
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\n" ); document.write( "\n" ); document.write( "The 95% confidence interval in the form (L, U) is (31.64, 48.36)\r
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\n" ); document.write( "\n" ); document.write( "Answer: (31.64, 48.36)\r
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\n" ); document.write( "\n" ); document.write( "We can write this in the form L < mu < U to say 31.64 < mu < 48.36
\n" ); document.write( "This format is more descriptive in that it's more clear that we're estimating mu here. \r
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\n" ); document.write( "\n" ); document.write( "Part (b)\r
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\n" ); document.write( "\n" ); document.write( "Now we're told that sigma = 10, while everything else is kept the same.\r
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\n" ); document.write( "\n" ); document.write( "Since we know sigma, we can use the Z distribution this time.\r
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\n" ); document.write( "\n" ); document.write( "Using a Z table, the critical value is roughly z = 1.960 at 95% confidence.\r
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\n" ); document.write( "\n" ); document.write( "Lower Bound
\n" ); document.write( "L = xbar - z*sigma/sqrt(n)
\n" ); document.write( "L = 40 - 1.960*10/sqrt(8)
\n" ); document.write( "L = 40 - 6.930
\n" ); document.write( "L = 33.07\r
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\n" ); document.write( "\n" ); document.write( "Upper Bound
\n" ); document.write( "U = xbar + z*sigma/sqrt(n)
\n" ); document.write( "U = 40 + 1.960*10/sqrt(8)
\n" ); document.write( "U = 40 + 6.930
\n" ); document.write( "U = 46.93\r
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\n" ); document.write( "\n" ); document.write( "As you can see, the format and structure of each formula is pretty much identical to the T distribution variety used in part (a). The only difference is that t has been replaced with z (so 2.365 is replaced with 1.960), and that we used sigma in place of s.\r
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\n" ); document.write( "\n" ); document.write( "Answer: (33.07, 46.93)\r
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\n" ); document.write( "\n" ); document.write( "This is equivalent to saying 33.07 < mu < 46.93
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