document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=606617>Question 606617</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A spends 1/4th of his leisure on reading books, 2/3rd of the remaining on watching TV. If he spends 2 hrs on watching TV what is the total time of his leisure? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #803701 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=803701\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1/4 = 3/12 of time reading books<BR>\n" );
document.write( "(2/3) * (3/4) = 1/2 of time on TV\r<BR>\n" );
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document.write( "x = total leisure time\r<BR>\n" );
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document.write( "x/2 = 2\r<BR>\n" );
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document.write( "x = 4 hours\r<BR>\n" );
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document.write( "**(corrected) </SPAN>\n" );
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