document.write( "Question 1176546: A tour bus normally leaves for its destination at
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Algebra.Com's Answer #803691 by ikleyn(52776) $\"\"$ $\"About$

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\n" ); document.write( "A tour bus normally leaves for its destination at 5:00 p.m. for a 300 mile trip. This week however, the bus leaves at 6:00 p.m.
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document.write( "Let x be its regular speed, in miles per hour.\r\n" );
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document.write( "Then the increased speed is (x+10) mph.\r\n" );
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document.write( "The regular travel time is    hours.\r\n" );
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document.write( "The travel time with increased speed is    hours.\r\n" );
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document.write( "The difference of traveled time is (from the context) 1 hour\r\n" );
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document.write( "     -  = 1  hour.\r\n" );
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document.write( "It is your time equation to find x.\r\n" );
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document.write( "You can guess the solution MENTALLY just from this point: it is  50 mph.     ANSWER\r\n" );
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document.write( "Indeed,   -  =  -  = 6 - 5 = 1 hour.\r\n" );
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document.write( "Or, alternatively, you may reduce equation (*) to quadratic equation and solve it formally.\r\n" );
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