document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=110316>Question 110316</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Factoring a quadratic wit leading coefficient greaer than 1<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #80367 by </B><A HREF=/tutors/aboutme.mpl?userid=wgunther><B>wgunther(43)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=wgunther><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=80367\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> For factoring quadratics with the leading coefficent greater than 1 is easy. I'll do a harder one that the one you listed (because leading coefficent prime it's actually the same as if it was 1, it will be in the for (3w+something)(w+something) if it's factorable)\r<BR>\n" );
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document.write( "Let<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=f%28x%29=4x%5E2%2B8x%2B3 ALIGN=MIDDLE  ALT=\"f%28x%29=4x%5E2%2B8x%2B3\"   DISABLED_style= \"max-width:90%; height:auto;\" >. Here your answer must in the form (2x+something)(2x+something) or (4x+something)(x+something) because the only way to multiple two integers to get 4 is 4 times 1 or 2 times 2. Then it's a guess and check time game. Clearly, the two contants in the factors have to be 3 and 1. So the only possibilities are (4x+1)(x+3) and (4x+3)(x+1) and (2x+1)(2x+3). Which one works?  </SPAN>\n" );
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