document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1176517>Question 1176517</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A car has an initial speed of 50 ft/s and an acceleration of - 4 ft/s2. In the first 10s after the acceleration begins, the car travels </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #803625 by </B><A HREF=/tutors/aboutme.mpl?userid=amarjeeth123><B>amarjeeth123(570)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amarjeeth123><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=803625\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Initial speed u=50ft/s<BR>\n" );
document.write( "Acceleration a=-4 ft/s2<BR>\n" );
document.write( "Time t=10s<BR>\n" );
document.write( "According to kinematics s=ut+(1/2)at^2 where s is the distance travelled<BR>\n" );
document.write( "Plugging in the values we get,<BR>\n" );
document.write( "s=50(10)+(1/2)(-4)(100)=500-200=300 ft.<BR>\n" );
document.write( "Distance traveled in the first 10 sec=300 ft.<BR>\n" );
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document.write( "</TD></TR></TABLE>\n" );