document.write( "Question 1175516: (Give your answers correct to TWO (2) decimal places)\r
\n" ); document.write( "\n" ); document.write( "In a time and motion study, the amount of time required to paint a 10-foot by 10-foot room is measured for 25 painters. The sample mean is calculated and found to be 72 minutes. If we assume that the population standard deviation is 5 minutes,\r
\n" ); document.write( "\n" ); document.write( "(a) find the 95% confidence interval estimate of the mean time for all painters to paint a 10-foot by 10-foot room.\r
\n" ); document.write( "\n" ); document.write( "Answer:the 95% confidence interval estimate of the mean time for all painters to paint a 10-foot by 10-foot room is from ____ minutes to ____minutes.\r
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\n" ); document.write( "\n" ); document.write( "(b) find the 97% confidence interval estimate of the mean time for all painters to paint a 10-foot by 10-foot room.\r
\n" ); document.write( "\n" ); document.write( "Answer: the 97% confidence interval estimate of the mean time for all painters to paint a 10-foot by 10-foot room is from____ minutes to____minutes.
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Algebra.Com's Answer #803603 by Theo(13342)\"\" \"About 
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sample size is 25
\n" ); document.write( "sample mean is 72 minutes
\n" ); document.write( "population standard deviation is 5 minutes.\r
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\n" ); document.write( "\n" ); document.write( "standard error = standard deviation / square root of sample size = 5 / sqrt(25) = 5/5 = 1.\r
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\n" ); document.write( "\n" ); document.write( "z-score = (x - m) / s\r
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\n" ); document.write( "\n" ); document.write( "x is the raw score
\n" ); document.write( "m is the raw mean
\n" ); document.write( "s is the standard error.\r
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\n" ); document.write( "\n" ); document.write( "at two tailed confidence level, the tails on each end of the confidence interval are 2.5%.\r
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\n" ); document.write( "\n" ); document.write( "the critical z-score is therefore equal to plus or minus 1.96.\r
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\n" ); document.write( "\n" ); document.write( "solve for the high raw score as follows:\r
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\n" ); document.write( "\n" ); document.write( "start with 1.96 = (x - 72) / 1\r
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\n" ); document.write( "\n" ); document.write( "solve for x to get x = 1.96 * 1 + 72 = 73.96.\r
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\n" ); document.write( "\n" ); document.write( "solve for the low raw score as follows:\r
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\n" ); document.write( "\n" ); document.write( "start with -1.96 = (x - 72) / 1\r
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\n" ); document.write( "\n" ); document.write( "solve for x to get x = -1.96 * 1 + 72 = 70.04\r
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\n" ); document.write( "\n" ); document.write( "your answer for question (a) is 70.04 to 73.96 minutes.\r
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\n" ); document.write( "\n" ); document.write( "with a two tailed 97% confidence level, the tails on each end of the confidence interval are 1.5%.\r
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\n" ); document.write( "\n" ); document.write( "the critical z-score becomes plus or minus 2.17.\r
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\n" ); document.write( "\n" ); document.write( "solve for the low and high raw score in the same manner as you did the the 95% confidence interval.\r
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\n" ); document.write( "\n" ); document.write( "you will get the low score equal to 69.83 and the high score equal to 74.17.\r
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\n" ); document.write( "\n" ); document.write( "visually, this looks like this.\r
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\n" ); document.write( "\n" ); document.write( "first 95% confidence interval, then 97% confidence interval.\r
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\n" ); document.write( "\n" ); document.write( "when dealing with the mean of a sample, you do not use the standard deviation.\r
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\n" ); document.write( "\n" ); document.write( "you use the standard error.\r
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\n" ); document.write( "\n" ); document.write( "the standard error is defined as the standard deviation of the distribution of sample means.\r
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\n" ); document.write( "\n" ); document.write( "here's a reference.\r
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\n" ); document.write( "\n" ); document.write( "https://www.investopedia.com/terms/s/standard-error.asp\r
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