document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1176499>Question 1176499</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the value of x in the range <BR>\n" );
document.write( "0°≤ x ≤ 360°, which satisfy the equation below. \r<BR>\n" );
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document.write( "(i) sin3xsinx = 2cos2x + 1\r<BR>\n" );
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document.write( "(ii) 1 + cosx = 2sin²x\r<BR>\n" );
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document.write( "(iii) 3cotx + tanx - 4 = 0<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #803596 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=803596\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ii. 1+ cos x=2-2 cos^2 x, because sin^2x=1-cos^2x<BR>\n" );
document.write( "2 cos^2x+ cos x-1=0<BR>\n" );
document.write( "(2 cos x-1)(cos x+1)=0<BR>\n" );
document.write( "cos x=1/2 (at 60 deg and 300 deg)<BR>\n" );
document.write( "cos x=-1 (at 180 deg)<BR>\n" );
document.write( "check with 60 deg<BR>\n" );
document.write( "1+0.5=2*3/4-1 checks<BR>\n" );
document.write( "at 300 deg checks as well<BR>\n" );
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