document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1004630>Question 1004630</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this problem:<BR>\n" );
document.write( "The length of a rectangle is 5 in longer than its width. The diagonal is 5 in shorter than twice the width. Find the length, width, and diagonal measures of the triangle.\r<BR>\n" );
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document.write( "My attempt:<BR>\n" );
document.write( "Length of rectangle= x + 5<BR>\n" );
document.write( "The length of the diagonal = 2x-5<BR>\n" );
document.write( "width = X \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #803581 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=803581\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (width)^2 + (length)^2 = (diagonal)^2\r<BR>\n" );
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document.write( "x^2 + (x+5)^2 = (2x - 5)^2<BR>\n" );
document.write( "x^2 + x^2 + 10x + 25 = 4x^2 - 20x + 25<BR>\n" );
document.write( "2x^2 + 10x + 25 = 4x^2 - 20x + 25<BR>\n" );
document.write( "0 = 2x^2 - 30x<BR>\n" );
document.write( "0 = 2(x)(x - 15)\r<BR>\n" );
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document.write( "x = 15 (distance can't be nonpositive)\r<BR>\n" );
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document.write( "width = x = 15<BR>\n" );
document.write( "length = x + 5 = 20<BR>\n" );
document.write( "diagonal = 2x - 5 = 25 </SPAN>\n" );
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