document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=957112>Question 957112</A>: <I><SPAN STYLE=\"word-break: break-all;\"> use the pythagorean theory to determine the value of x and the measurments of each side of the right triangle. <BR>\n" );
document.write( "one side:5x<BR>\n" );
document.write( "second side: x+8<BR>\n" );
document.write( "thrid side: 5x-4\r<BR>\n" );
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document.write( "solve for x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #803566 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=803566\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I'm assuming the third side is the hypotenuse.\r<BR>\n" );
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document.write( "(5x)^2 + (x + 8)^2 = (5x - 4)^2<BR>\n" );
document.write( "25x^2 + x^2 + 16x + 64 = 25x^2 - 40x + 16<BR>\n" );
document.write( "x^2 + 16x + 64 = -40x + 16<BR>\n" );
document.write( "x^2 + 56x + 48 = 0\r<BR>\n" );
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document.write( "Use the quadratic formula to find x. </SPAN>\n" );
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