document.write( "Question 379040: Solve: 3+|2y-1|≥1. Graph the solution set on a number line. \n" ); document.write( "

Algebra.Com's Answer #803439 by ikleyn(52781) $\"\"$ $\"About$

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\n" ); document.write( "Solve: 3 + |2y-1| ≥ 1. Graph the solution set on a number line.
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\n" ); document.write( "\n" ); document.write( " The solution by @Penguin is INCORRECT.\r
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\n" ); document.write( "\n" ); document.write( " I came to bring you a correct solution.\r
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document.write( "You start with this inequality\r\n" );
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document.write( "    3 + |2y-1| >= 1.\r\n" );
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document.write( "Next you subtract the number 3 from both sides.\r\n" );
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document.write( "    |2y-1| >= 1 - 3,\r\n" );
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document.write( "or\r\n" );
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document.write( "    |2y-1| >= -2.\r\n" );
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document.write( "But the absolute value is ALWAYS NON-NEGATIVE number,\r\n" );
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document.write( "so the last inequality is valid FOR ANY VALUE of y.\r\n" );
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document.write( "ANSWER.  The solution set is the ENTIRE NUMBER LINE from -oo to oo.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Solved, answered, explained and completed.\r
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\n" ); document.write( "\n" ); document.write( "Ignore the post by @Pinguin, since it is T O T A L L Y W R O N G.\r
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