document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=110211>Question 110211</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can someone help me solve this. I have to factor trinomials using the AC method. <BR>\n" );
document.write( "20x^2-20x-15 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #80339 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=80339\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5 is common to all the terms ...5(4x^2-4x-3)\r<BR>\n" );
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document.write( "AC means take the factors of the product of a and c, and try to add them to get b\r<BR>\n" );
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document.write( "4(-3)=-12 ... factors are 1, 2, 3, 4, 6, 12 ... 2 and -6 add to -4\r<BR>\n" );
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document.write( "(4x+2)(4x-6) ... reduce coefficients by common factors (2 in this case) ...(2x+1)(2x-3)\r<BR>\n" );
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document.write( "5(2x+1)(2x-3) </SPAN>\n" );
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