document.write( "Question 110273: how do i solve 1/3 x+ 3/4x=13
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\n" ); document.write( "-2x + 4 > 12
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Algebra.Com's Answer #80337 by stanbon(75887)\"\" \"About 
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solve 1/3 x+ 3/4x=13
\n" ); document.write( "Multiply both sides by 12 to get:
\n" ); document.write( "4x + 9x = 13*12
\n" ); document.write( "13x = 13*12
\n" ); document.write( "x = 12
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\n" ); document.write( "and
\n" ); document.write( "-2x + 4 > 12
\n" ); document.write( "Add 2x to both sides to get:
\n" ); document.write( "4 > 2x+12
\n" ); document.write( "Divide thru by 2 to get:
\n" ); document.write( "2 > x+6
\n" ); document.write( "Subtract 6 from both sides to get:
\n" ); document.write( "x < -4
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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