document.write( "Question 1176443: Hi
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document.write( "In a class of 40 the average score was 70.25. The average scores for boys and girls were 68 and 73 respectively. How many boys were in the class.
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document.write( "Thanks \n" );
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Algebra.Com's Answer #803369 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "The other tutor has provided a good solution using the standard formal algebraic method for solving problems like this. \n" ); document.write( "This, and a large number of other types of problems, can be seen as a weighted average problem, or a mixture problem. Problems like that can be solved by seeing where the weighted average lies between the two given averages. \n" ); document.write( "Consider the overall (weighted) average and the averages of the boys and girls on a number line: 68, 70.25, and 73. \n" ); document.write( "With simple arithmetic, determine that the class average lies 2.25/5 = 9/20 of the way from 68 to 73. \n" ); document.write( "That means 9/20 of the students in the class are girls. \n" ); document.write( "9/20 of 40 is 18, so there are 18 girls in the class; that means 22 boys. \n" ); document.write( " \n" ); document.write( " |