document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1168205>Question 1168205</A>: <I><SPAN STYLE=\"word-break: break-all;\"> There are approximately 500 wolves in Algonquin Provincial Park. Under ideal conditions, this population would<BR>\n" );
document.write( "double every 35 years<BR>\n" );
document.write( "a. Which equation models this population growth?<BR>\n" );
document.write( "b. How many wolves were in the park 10 years ago? (time will be negative)<BR>\n" );
document.write( "c. How long till the population of wolves would triple? <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #803286 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=803286\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Rule of 70: 70/35 = 2%\r<BR>\n" );
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document.write( "a. (500)(1.02)^x for x years\r<BR>\n" );
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document.write( "b. (500)(1.02)^(-10) = 410 (rounded to the nearest integer)\r<BR>\n" );
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document.write( "c. (500)(1.02)^x = 1500<BR>\n" );
document.write( "1.02^x = 3\r<BR>\n" );
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document.write( "x = log_(1.02)(3) = 55.47 years </SPAN>\n" );
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