document.write( "Question 1176386: Consider the following grouped frequency distribution, which portrays the duration (in minutes) of 50 lectures
\n" );
document.write( "delivered by a Chemistry professor.\r
\n" );
document.write( "\n" );
document.write( "Duration (Minutes) Frequency
\n" );
document.write( "30.00 < 40.00 3
\n" );
document.write( "40.00 < 50.00 7
\n" );
document.write( "50.00 < 60.00 18
\n" );
document.write( "60.00 < 70.00 13
\n" );
document.write( "70.00 < 80.00 8
\n" );
document.write( "80.00 < 90.00 1\r
\n" );
document.write( "
\n" );
document.write( "\n" );
document.write( "Using computational formulae, calculate the:\r
\n" );
document.write( "\n" );
document.write( "(i) estimated mean.
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #803183 by Solver92311(821)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "To calculate the estimated mean: Find the midpoint of each interval. Multiply the midpoints by the associated frequencies. Add the products. Divide the sum by the total number of data observations (sum of the frequency numbers).\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " ![]() \n" ); document.write( "\n" ); document.write( "From \n" ); document.write( "I > Ø \n" ); document.write( " |