document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=994136>Question 994136</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the diagonal of a rectangular lot is 6 m. the length of one side of the lot is 1more than the other. find the lengths of the sides of the lot.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #803141 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=803141\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> width = w<BR>\n" );
document.write( "length = w + 1\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "w^2 + (w + 1)^2 = 36<BR>\n" );
document.write( "2w^2 + 2w - 35 = 0\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "w = (sqrt(71) - 1)/2<BR>\n" );
document.write( "length = (sqrt(71) + 1)/2 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );