document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=997650>Question 997650</A>: <I><SPAN STYLE=\"word-break: break-all;\"> one positive number exceeds twice another number by 3 and the product of the two numbers is 44. Find the smaller number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #803134 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=803134\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = smaller number<BR>\n" );
document.write( "y = larger number\r<BR>\n" );
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document.write( "y = 2x + 3<BR>\n" );
document.write( "xy = 44\r<BR>\n" );
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document.write( "Substitute.\r<BR>\n" );
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document.write( "x(2x + 3) = 44<BR>\n" );
document.write( "2x^2 + 3x - 44 = 0<BR>\n" );
document.write( "(2x + 11)(x - 4) = 0\r<BR>\n" );
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document.write( "The numbers are positive, so smaller = 4 and larger = 11. </SPAN>\n" );
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