document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1005642>Question 1005642</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the dimensions of a rectangle whose width is 1 inches less than half its length an whose area is 40 square inches. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #803101 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=803101\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> length = L<BR>\n" );
document.write( "width = L/2 - 1\r<BR>\n" );
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document.write( "L(L/2 - 1) = 40<BR>\n" );
document.write( "L^2/2 - L = 40<BR>\n" );
document.write( "L^2 - 2L - 80 = 0<BR>\n" );
document.write( "(L - 10)(L + 8) = 0\r<BR>\n" );
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document.write( "dimensions: 10 inches by 4 inches </SPAN>\n" );
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