document.write( "Question 16472: I am laying out a peice of furniture and wish to make a pattern.\r
\n" ); document.write( "\n" ); document.write( "I wish to know the radius of a circle that will subtend a cord of 30 \" with a height of 2 1/2\". \r
\n" ); document.write( "\n" ); document.write( "I am 73 and took geometry in 1947 - I seem to have forgotten the formulas.\r
\n" ); document.write( "\n" ); document.write( "Thanks,\r
\n" ); document.write( "\n" ); document.write( "Wyatt Shorter
\n" ); document.write( "

Algebra.Com's Answer #8031 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
HI Wyatt, here's a formula that could help solve your problem. If you're interested, it came out of a math tables book (CRC Standard Mathematical Tables) which I have used since the early fifties in college.\r
\n" ); document.write( "\n" ); document.write( "\"C+=+sqrt%284h%282R+-+h%29%29\"\r
\n" ); document.write( "\n" ); document.write( "Since you know C (the chord length) and h (the length of that part of the radius between the chord and the circumference), you can, with a little algebraic manipulation, solve for R, the radius.\r
\n" ); document.write( "\n" ); document.write( "\"C+=+sqrt%284h%282R+-+h%29%29\" Square both sides.
\n" ); document.write( "\"C%5E2+=+4h%282R+-+h%29\" Divide both sides by 4h.
\n" ); document.write( "\"C%5E2%2F4h+=+2R+-+h\" Add h to both sides.
\n" ); document.write( "\"%28C%5E2%2F4h%29+%2B+h+=+2R\" Finally, divide both sides by 2.
\n" ); document.write( "\"%28%28C%5E2%2F4h%29+%2B+h%29%2F2+=+R\" This can be simplified a bit.
\n" ); document.write( "\"R+=+%28C%5E2+%2B+4h%5E2%29%2F8h\"\r
\n" ); document.write( "\n" ); document.write( "Now let's plug in your values of C (30\") and h (2.5\") and grind away.\r
\n" ); document.write( "\n" ); document.write( "\"R+=+%2830%5E2+%2B+4%282.5%29%5E2%29%2F8%282.5%29\"
\n" ); document.write( "\"R+=+%28900+%2B+4%286.25%29%29%2F20\"
\n" ); document.write( "\"R+=+%28925%29%2F20\"
\n" ); document.write( "\"R+=+46.25\" inches.
\n" ); document.write( "
\n" );