document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=963366>Question 963366</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sides of a triangle have lengths of x,x+4,and 20.If the longest side is 20,Which of the following values of x would make the triangle obtuse<BR>\n" );
document.write( "A.8<BR>\n" );
document.write( "B.10<BR>\n" );
document.write( "C.12<BR>\n" );
document.write( "D.15<BR>\n" );
document.write( "Thank you stephanie </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #803090 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=803090\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x^2 + (x + 4)^2 = 20^2<BR>\n" );
document.write( "2x^2 + 8x + 16 = 400<BR>\n" );
document.write( "x^2 + 4x + 8 = 200<BR>\n" );
document.write( "x^2 + 4x - 192 = 0<BR>\n" );
document.write( "(x + 16)(x - 12) = 0\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "x = 12 for the triangle to be right. Anything less makes it acute and anything more makes it obtuse, so the answer is D. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );