document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1060661>Question 1060661</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of rectangle is four more than twice of its weiht.Find the length and weight if the perimeter is 60cm. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #803057 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=803057\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> width = w<BR>\n" );
document.write( "length = 2w + 4\r<BR>\n" );
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document.write( "perimeter = 2(w) + 2(2w + 4) = 60<BR>\n" );
document.write( "2w + 4w + 8 = 60<BR>\n" );
document.write( "6w = 52\r<BR>\n" );
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document.write( "width = w = 26/3<BR>\n" );
document.write( "length = 2w + 4 = 64/3 </SPAN>\n" );
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