document.write( "Question 1176309: A movie theater has a seating capacity of 291. The theater charges $5.00 for children, $7.00 for students, and $12.00 of adults. There are half as many adults as there are children. If the total ticket sales was $2116, How many children, students, and adults attended? \n" ); document.write( "

Algebra.Com's Answer #802916 by ikleyn(52776) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( "We assume that all 291 tickets are sold.\r
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document.write( "Let \"a\" be the number of adults;  then the number of children is  (2a).\r\n" );
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document.write( "The number of students is the rest, (291-a-2a) = 291-3a.\r\n" );
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document.write( "The \"money\" equation is\r\n" );
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document.write( "    12a + 5*(2a) + 7*(291-3a) = 2116  dollars.\r\n" );
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document.write( "Simplify and solve for \"a\".\r\n" );
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document.write( "    12a + 10a + 7*207 - 21a = 2116 - 7*291,\r\n" );
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document.write( "    a = 79.\r\n" );
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document.write( "ANSWER.  79 adults;  2*79 = 158 children  and  (291-3*79) = 54 students.\r\n" );
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document.write( "CHECK.  79*12 + 5*158 + 54*7 = 2116  dollars, total revenue.   ! Correct !\r\n" );
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\n" ); document.write( "\n" ); document.write( "This problem is to be solved using one equation in one unknown.\r
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\n" ); document.write( "\n" ); document.write( "If you want to see many other similar solved problems, look into the lessons\r
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