document.write( "Question 1176305: In a school,1200 of the students are boys,if 50% of the boys and 40% of the girls have paid their school fees. Find the number of girls,given that 46% of the population have paid their school fees. \n" ); document.write( "
Algebra.Com's Answer #802913 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "let the number of boys be \"b\" and the number of girls be \"g\" \r
\n" ); document.write( "\n" ); document.write( "given:\r
\n" ); document.write( "\n" ); document.write( "\"b%2Bg=1200\"
\n" ); document.write( "\"b=1200-g\".......eq.1\r
\n" ); document.write( "\n" ); document.write( "if \"50\"% of the boys and \"40\"% of the girls have paid their school fees, we have\r
\n" ); document.write( "\n" ); document.write( "\"0.50b+\"and \"0.40g\" have paid their school fees\r
\n" ); document.write( "\n" ); document.write( "if given that \"46\"% of the population have paid their school fees. then \r
\n" ); document.write( "\n" ); document.write( "\"0.46%2A1200=552\" have paid their school fees\r
\n" ); document.write( "\n" ); document.write( "so \r
\n" ); document.write( "\n" ); document.write( "\"0.50b+%2B0.40g=552\"........eq.2, substitute \"b\" from eq.1
\n" ); document.write( "\"0.50%281200-g%29+%2B0.40g=552\"
\n" ); document.write( "\"600-0.50g+%2B0.40g=552\"
\n" ); document.write( "\"600-0.10g+=552\"
\n" ); document.write( "\"600-552=0.10g+\"
\n" ); document.write( "\"48=0.10g+\"
\n" ); document.write( "\"g=48%2F0.10\"
\n" ); document.write( "\"g=480\"\r
\n" ); document.write( "\n" ); document.write( "\"b=1200-480\".......eq.1
\n" ); document.write( "\"b=720\"\r
\n" ); document.write( "\n" ); document.write( "\"50\"% of the boys, which is \"0.50%2A720=360\" boys, have paid their school fees\r
\n" ); document.write( "\n" ); document.write( "and \r
\n" ); document.write( "\n" ); document.write( "\"40\"% of the girls, which is \"0.40%2A480=192\" girls, have paid their school fees\r
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