document.write( "Question 693272: (3x - 10) / (x - 4) >2 \n" ); document.write( "
Algebra.Com's Answer #802905 by ikleyn(52781)\"\" \"About 
You can put this solution on YOUR website!
(3x - 10) / (x - 4) > 2
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\n" ); document.write( "\n" ); document.write( "            The solution in the post by  @CubeyThePenguin is  ABSOLUTELY  WRONG.\r
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\n" ); document.write( "\n" ); document.write( "            I came to bring the correct solution.\r
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document.write( "Transform the inequality, using equivalent transformations\r\n" );
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document.write( "    \"%283x-10%29%2F%28x-4%29\" > 2\r\n" );
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document.write( "    \"%283x-10%29%2F%28x-4%29\" - 2 > 0\r\n" );
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document.write( "    \"%283x-10%29%2F%28x-4%29\" - \"2%2A%28%28x-4%29%2F%28x-4%29%29\" > 0\r\n" );
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document.write( "    \"%28%283x-10%29+-+2%2A%28x-4%29%29%2F%28x-4%29\" > 0\r\n" );
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document.write( "    \"%283x+-+10+-+2x+%2B+8%29%2F%28x-4%29\" > 0\r\n" );
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document.write( "    \"%28x+-2%29%2F%28x-4%29\" > 0    (*)\r\n" );
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document.write( "Inequality (*) is equivalent to the given inequality.\r\n" );
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document.write( "There are two critical points x= 2 and x= 4, that divide the number line in three non-intersecting intervals\r\n" );
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document.write( "          (-oo,2), (2,4) and (4,oo).\r\n" );
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document.write( "In the first interval, both the numerator and denominator of (*) are negative;  so the inequality (*) is valid; \r\n" );
document.write( "so the interval (-oo,2)  is the part of the solution set.\r\n" );
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document.write( "In the second interval, the numerator of (*) is positive, while the denominator of (*) is negative;  \r\n" );
document.write( "so the inequality (*) is not valid; thus the interval (2,4)  is NOT the part of the solution set.\r\n" );
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document.write( "In the third interval, both the numerator and denominator of (*) are positive;  so the inequality (*) is valid; \r\n" );
document.write( "so the interval (4,oo)  is the part of the solution set.\r\n" );
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document.write( "ANSWER.  The solution set to the given inequality is the union of two intervals  (-oo,2) U (4,oo).\r\n" );
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