document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1176251>Question 1176251</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One grocery clerk can stock a shelf in 30 min. A second cleck requires 45 min to stock the same shelf. How long would it take to stock the shelf if the two clerks worked together? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #802756 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=802756\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Here is an alternative to the standard algebraic method for solving problems like this as shown by the other tutor.<br><BR>\n" );
document.write( "The least common multiple of the two given times is 90 minutes.<br><BR>\n" );
document.write( "In 90 minutes the first clerk could stock 90/30 = 3 shelves; the other could stock 90/45 = 2 shelves.<br><BR>\n" );
document.write( "So together in 90 minutes the two clerks could stcok 3+2=5 shelves; that means they can stock the one shelf if 90/5 = 18 minutes.<br><BR>\n" );
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