document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1176248>Question 1176248</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jhon and Sam have a lawn mowing service. At one home, Jhon can mow the lawn by himself in 1 hours, but it takes Sam 1.5 hours. How many hours t will it take them to mow the same lawn together? Give the answer correct to one decimal place. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #802755 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=802755\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Here is an alternative to the standard algebraic solution method show by the other tutor.<br><BR>\n" );
document.write( "Consider the least common multiple of the two given times.  The LCM of 1 hour and 1.5 hours is 3 hours.<br><BR>\n" );
document.write( "In 3 hours the number of such lawns Jhon could mow is 3/1 = 3; in 3 hours the number Sam could mow is 3/1.5 = 2.<br><BR>\n" );
document.write( "So in 3 hours the two of them together could mow 3+2=5 lawns.  And that means together they can mow the one lawn in 3/5 hours, or 36 minutes.<br><BR>\n" );
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