document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1176241>Question 1176241</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the standard form of the equation of the circle with the given characteristics.\r<BR>\n" );
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document.write( "Center: (-3, 2);   point on circle: (-6, 4)<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #802693 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=802693\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The radius is the sqrt (diff in x^2+ diff in y ^2)=sqrt(9+4)=sqrt(13)<BR>\n" );
document.write( "change the signs of the center<BR>\n" );
document.write( "(x+3)^2+(y-2)^2=13<BR>\n" );
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