document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1176215>Question 1176215</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of the second and third terms of a geometric sequence is 18 . If the tenth term is 8 times the seventh term , find ; <BR>\n" );
document.write( "a) the first term<BR>\n" );
document.write( " b) the common ratio <BR>\n" );
document.write( "c) the sixth term </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #802574 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=802574\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First term = a, common ratio = r\r<BR>\n" );
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document.write( "ar + ar^2 = 18<BR>\n" );
document.write( "ar^9 = 8(ar^6)\r<BR>\n" );
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document.write( "We get r^3 = 2, so r = 2 and a = 3.\r<BR>\n" );
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document.write( "sixth term = ar^5 = 3(2)^5 = 96.<BR>\n" );
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