document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1125605>Question 1125605</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Show that the given function is one-to-one and find its inverse. Check your answers algebraically and graphically. Verify that the range of f is the domain of f inverse and vice-versa.\r<BR>\n" );
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document.write( "f(x)=6-5&#8731;(x-8)<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #802554 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=802554\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve for x.\r<BR>\n" );
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document.write( "y = 6 - 5cbrt(x - 8)\r<BR>\n" );
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document.write( "y - 6 = 5cbrt(x - 8)\r<BR>\n" );
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document.write( "(y-6)^3 = 125(x - 8)\r<BR>\n" );
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document.write( "(y-6)^3/125 = x - 8\r<BR>\n" );
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document.write( "f^(-1)(x) = ((x-6)^3/125) + 8 </SPAN>\n" );
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