document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=110164>Question 110164</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help!!!\r<BR>\n" );
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document.write( "(4x+4)/5 = (5x-1)/2 - x/3  You must show all work to receive full credit.\r<BR>\n" );
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document.write( "Show work here:\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #80255 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=80255\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (4X+4)/5=(5X-1)/2-X/3 FIND A COMMON DENOMINATOR FOR THE RIGHT HAND TERMS. <BR>\n" );
document.write( "(4X+4)/5=[3(5X-1)-2X]/2*3<BR>\n" );
document.write( "(4X+4)/5=(15X-3-2X)/6<BR>\n" );
document.write( "(4X+4)/5=(13X-3)/6 NOW CROSS MULTIPLY.<BR>\n" );
document.write( "6(4X+4)=5(13X-3)<BR>\n" );
document.write( "24X+24=65X-15<BR>\n" );
document.write( "24X-65X=-15-24<BR>\n" );
document.write( "-41X=-39<BR>\n" );
document.write( "X=-39/-41<BR>\n" );
document.write( "X=39/41 OR .95 NSWER. </SPAN>\n" );
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