document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=997647>Question 997647</A>: <I><SPAN STYLE=\"word-break: break-all;\"> on a right triangle, one leg is two more than twice the other. the hypotenuse is one more than the longer leg. find the sides<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #802547 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=802547\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> shortest leg = x\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "x^2 + (2x + 2)^2 = (2x + 3)^2<BR>\n" );
document.write( "3x^2 + 8x + 4 = 4x^2 + 12x + 9\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "x = -1 or 5\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Distance can't be negative, so the side lengths are 5, 12, and 13. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );