document.write( "Question 1176203: An old printing press takes 5 hours longer to put out a daily paper than does a new press. If the two press work together, the job takes 6 hours. How long does it take each press to put out the paper on its own? \n" ); document.write( "

Algebra.Com's Answer #802546 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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An old printing press takes 5 hours longer to put out a daily paper than does a new press.
\n" ); document.write( " If the two press work together, the job takes 6 hours.
\n" ); document.write( " How long does it take each press to put out the paper on its own?
\n" ); document.write( ":
\n" ); document.write( "let t = time required by the new press to do the job
\n" ); document.write( "then
\n" ); document.write( "(t+5) = time required by the old press
\n" ); document.write( "let the completed job = 1
\n" ); document.write( ":
\n" ); document.write( "Each will do a fraction of the job, the two fractions add up to 1
\n" ); document.write( " $\"6%2Ft\"$ + $\"6%2F%28%28t%2B5%29%29\"$ = 1
\n" ); document.write( "Multiply by t(t+5), cancel the denominators
\n" ); document.write( "6(t+5) + 6t = t(t+5)
\n" ); document.write( "6t + 30 + 6t = t^2 + 5t
\n" ); document.write( "12t + 30 = t^2 + 5t
\n" ); document.write( "form a quadratic on the right'
\n" ); document.write( "0 = t^2 + 5t - 12t - 30
\n" ); document.write( "t^2 - 7t - 30 = 0
\n" ); document.write( "Factors to
\n" ); document.write( "(t-10)(t+3) = 0
\n" ); document.write( "positive solution is all we want here
\n" ); document.write( "t = 10 hrs required by the new press
\n" ); document.write( "then, obviously
\n" ); document.write( "15 hrs required by to old press
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "See if that works
\n" ); document.write( " $\"6%2F10\"$ + $\"6%2F15\"$ =
\n" ); document.write( " $\"3%2F5\"$ + $\"2%2F5\"$ = 1\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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