document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=964430>Question 964430</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rhombus has sides of lenght 10cm. One of its diagonals is twice as long as the other. Calculate the length of the shorter diagonal to the nearestt mm. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #802542 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=802542\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> length of short diagonal = x\r<BR>\n" );
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document.write( "side = sqrt((x/2)^2 + x^2) = 10\r<BR>\n" );
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document.write( "5x^2/4 = 100\r<BR>\n" );
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document.write( "x^2 = 80\r<BR>\n" );
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document.write( "x = sqrt(80) which is about 9 mm </SPAN>\n" );
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