document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1001339>Question 1001339</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the hypotenuse is 14 meters and one leg is 3 meters shorter than the other, what are the lengths of the leg </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #802539 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=802539\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> shorter leg = x\r<BR>\n" );
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document.write( "x^2 + (x+3)^2 = 14^2<BR>\n" );
document.write( "2x^2 + 6x + 9 = 196<BR>\n" );
document.write( "2x^2 + 6x - 187 = 0\r<BR>\n" );
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document.write( "x = -3/2 + sqrt(383)/2 which is roughly 8.29 m. </SPAN>\n" );
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