document.write( "Question 1176178: Suppose that the price per unit in dollars of a cell phone production is modeled by p=$45-0.0125x, where x is in thousands of phones produced, and the revenue represented by thousands of dollars is R=x•p. Find the production level that will maximize revenue. \n" ); document.write( "

Algebra.Com's Answer #802505 by ikleyn(52777) $\"\"$ $\"About$

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document.write( "The revenue is \r\n" );
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document.write( "    R(x) = x*(45-0.0125x) dollars.\r\n" );
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document.write( "This formula represents  a quadratic function, whose plot is a parabola opened downward.\r\n" );
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document.write( "It gets the maximum at the value of x which is exactly midway between the x-intersections.\r\n" );
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document.write( "The x-intersections are  x= 0  and  x=  = 3200,\r\n" );
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document.write( "so the maximum of the function is at  x= 1600,\r\n" );
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document.write( "To get the value of the maximum, substitute  x= 1600 into the Revenue formula\r\n" );
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document.write( "     = 1600*(45-0.0125*1600) = 40,000 thousand dollars.    ANSWER\r\n" );
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