document.write( "Question 1176182: In Jacks piggy bank, there is a collection of pennies, nickels, dimes, and quarters which amounts to $2.87. The number of quarters is one less than twice the number of nickels. There are 4 more pennies than nickels. The number of dimes is twice the number of pennies. How many coins of each kind are there? \n" ); document.write( "
Algebra.Com's Answer #802480 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "You could solve this using 4 variables, one for the number of each type of coin. But I think it is far easier if you take the time to understand the given information to set up the problem using a single variable. Then you will have a single equation to solve, rather than a system of 4 equations with 4 variables. \n" ); document.write( "The way I read the given information, it will be easiest to use the number of nickels as our variable. So \n" ); document.write( "x = number of nickels \n" ); document.write( "2x-1 = number of quarters (1 less than twice the number of nickels) \n" ); document.write( "x+4 = number of pennies (4 more than the number of nickels) \n" ); document.write( "2(x+4) = 2x+8 = number of dimes (twice the number of pennies) \n" ); document.write( "Use those expressions and the value of each kind of coin to write and solve an equation that says the total value of the coins is $2.87, or 287 cents: \n" ); document.write( "5(x)+25(2x-1)+1(x+4)+10(2x+8) = 287 \n" ); document.write( "5x + 50x-25 + x+4 + 20x+80 = 287 \n" ); document.write( "76x+59 = 287 \n" ); document.write( "76x = 228 \n" ); document.write( "x = 3 \n" ); document.write( "ANSWERS: The number of each type of coin is \n" ); document.write( "nickels: x = 3 \n" ); document.write( "quarters: 2x-1 = 5 \n" ); document.write( "pennies: x+4 = 7 \n" ); document.write( "dimes: 2x+8 = 14 \n" ); document.write( "CHECK: 3(5)+5(25)+7(1)+14(10) = 15+125+7+140 = 287 \n" ); document.write( " \n" ); document.write( " |