document.write( "Question 110134: I am stuck on this problem! \r
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document.write( "At one p.m., 1/5 of the geese fly away. At two p.m., 1/8 of the geese fly away. At three p.m., three times as many geeseflew away as one p.m. There are now 28 geese left at the pond. How many geese were in the original flock?\r
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document.write( "I tried this equation: X-1/5x-1/8x-3/5x = 28, but get 373.333 or 373 and 1/3rd geese? What am i doing wrong? Thanks \n" );
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Algebra.Com's Answer #80245 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Let x=number of geese in the original flock \n" ); document.write( "At one pm, x/5 fly away \n" ); document.write( "and at one pm, we have left x-x/5=4x/5 geese \n" ); document.write( "At two pm (1/8)(4x/5) or(4x/40) or (x/10) fly away-------------Now I'm assuming that you mean 1/8 of the geese that are left \n" ); document.write( "At two pm, (4x/5)-(x/10) or (8x/10)-(x/10) or 7x/10 geese are left\r \n" ); document.write( "\n" ); document.write( "At three pm, 3*(x/5) flew away that means that \n" ); document.write( "At three pm, (7x/10)-(3x/5) or (7x/10)-6x/10) or x/10 geese are left and we are told that this equals 28.--------------So:\r \n" ); document.write( "\n" ); document.write( "x/10=28 multiply both sides by 10 \n" ); document.write( "x=280-----------------------------------number of geese in the original flock\r \n" ); document.write( "\n" ); document.write( "CK \n" ); document.write( "at one pm, 280/5 or 56 geese flew away leaving 280-56 or 224\r \n" ); document.write( "\n" ); document.write( "at two pm 224/8 or 28 geese flew away leaving 224-28 or 196\r \n" ); document.write( "\n" ); document.write( "At three pm 3*56 or 168 geese flew away leaving 196-168 or 28\r \n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor \n" ); document.write( " |