document.write( "Question 965860: If you have to pay $75.00 and have 27 bills of $1.00 and $5.00, how many bills do you need of $1.00 and $5.00 to pay. \n" ); document.write( "

Algebra.Com's Answer #802444 by greenestamps(13200) $\"\"$ $\"About$

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\n" ); document.write( "The language use in the statement of the problem is definitely poor, leaving the problem open to different interpretations. With one interpretation of the problem, you could pay the $75 with 15 $5 bills and still have 12 bills (of either $1 or $5 denominations) left.

\n" ); document.write( "Assuming the intent of the problem is to use exactly all 27 bills to make the payment, the solution by the other tutor is a good typical algebraic solution.

\n" ); document.write( "You can get good mental exercise by solving a problem like this using logical reasoning and simple mental arithmetic, perhaps like this:

\n" ); document.write( "The total to be paid is $75; since any number of $5 bills makes a total that is a multiple of $5, the total value of the $1 bills must also be a multiple of 5. So the number of $1 bills is either 5, 10, 15, 20, or 25.

\n" ); document.write( "Then a few quick mental calculations show the correct total is with 15 $1 bills: 15($1)+12($5) = $15+$60 = $75

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