document.write( "Question 1176098: The mean and variance of a Binomial variable X with parameters n and p are 16 and 8. Find P(X1) and P(X>2).
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Algebra.Com's Answer #802431 by Boreal(15235)\"\" \"About 
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the mean is np=16
\n" ); document.write( "the variance is np (1-p)=8
\n" ); document.write( "so 16(1-p)=8
\n" ); document.write( "1-p=1/2
\n" ); document.write( "p=0.50
\n" ); document.write( "n=32
\n" ); document.write( "p=0.5
\n" ); document.write( "mean 16
\n" ); document.write( "variance 8
\n" ); document.write( "probability x=1 is 32C)*0.5^1*0.5^31=7 x 10^(-9)
\n" ); document.write( "probability x>2 is 1- probability x=2 essentially, which is 1=32C2*0.5^32=1.
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