document.write( "Question 990538: When a certain number is divided by 2, there is a remainder of 1. When the same number is divided by 3, 4 and 5, there are remainders of 2, 3, and 4 respectively. What is the smallest positive number for which the conditions are satisfied? \n" ); document.write( "
Algebra.Com's Answer #802425 by ikleyn(52798)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( "If you add 1 to the number, you will get the number multiple of 2, 3, 4, 5.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "The smallest such a number is LCM(2,3,4,5) = 60.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "THEREFORE, the number under the problem's question is 60-1 = 59. ANSWER\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |