document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1008430>Question 1008430</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A woman is three times as old as her daughter. six years ago, the sum of their ages was 36. find the age of the daughter. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #802257 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=802257\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = woman's age<BR>\n" );
document.write( "y = daughter's age\r<BR>\n" );
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document.write( "x = 3y<BR>\n" );
document.write( "(x-6)+(y-6) = 36\r<BR>\n" );
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document.write( "Plug in the first equation into the second.\r<BR>\n" );
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document.write( "x + y = 36 + 12 = 48<BR>\n" );
document.write( "4y = 48<BR>\n" );
document.write( "y = 12\r<BR>\n" );
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document.write( "The daughter is 12 years old. </SPAN>\n" );
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