document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=110117>Question 110117</A>: <I><SPAN STYLE=\"word-break: break-all;\"> an outboard motor calls for a fuel mixture of gasoline and oil to be 50 to 1. That is, 50 parts of gasoline to 1 part of oil. How many pints of oil should be added to 6 gallons of gasoline? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #80225 by </B><A HREF=/tutors/aboutme.mpl?userid=bucky><B>bucky(2189)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bucky><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=80225\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You can work this problem as a proportion, but you have to be careful of the units.<BR>\n" );
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document.write( "First you are told that the ratio you want to have is 50 parts of gasoline to 1 part of oil.<BR>\n" );
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document.write( "This ratio is 50:1 or in fractional form <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=50%2F1 ALIGN=MIDDLE  ALT=\"50%2F1\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
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document.write( "Next you can recognize that the gasoline is on top of this fraction and the oil is in the<BR>\n" );
document.write( "denominator. Therefore, the next ratio is 6 gallons of gasoline to an unknown amount of<BR>\n" );
document.write( "oil. Call this unknown amount of oil x. The proportion then becomes:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=50%2F1+=+6%2Fx ALIGN=MIDDLE  ALT=\"50%2F1+=+6%2Fx\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "The right side simplifies to just 50 ... 1 into 50 equals 50 ... and the proportion <BR>\n" );
document.write( "becomes:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=50+=+6%2Fx ALIGN=MIDDLE  ALT=\"50+=+6%2Fx\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Next you can get rid of the denominator on the right side by multiplying both sides of<BR>\n" );
document.write( "this proportion by x. When you do the proportion is simplified to just an equation:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=50x+=+6 ALIGN=MIDDLE  ALT=\"50x+=+6\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Now keep in mind that the 6 on the right side is in units of gallons. How many pints are there<BR>\n" );
document.write( "in 6 gallons?  There are 2 pints in a quart and 4 quarts in a gallon. Therefore, each gallon<BR>\n" );
document.write( "contains 2*4 = 8 pints. And since there are 6 total gallons at 8 pints per gallon there<BR>\n" );
document.write( "are a total of 6*8 = 48 pints in 6 gallons.<BR>\n" );
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document.write( "Switch from gallons to pints by replacing the 6 gallons with 48 pints, making the equation<BR>\n" );
document.write( "become:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=50x+=+48 ALIGN=MIDDLE  ALT=\"50x+=+48\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "Solve for x (which is the number of pints of oil to be added to 6 gallons of gas to give<BR>\n" );
document.write( "a 50 to 1 gas to oil mix) by dividing both sides of the equation by 50 to get:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+48%2F50+=+0.96 ALIGN=MIDDLE  ALT=\"x+=+48%2F50+=+0.96\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "So the answer is that for a 50 to 1 mix, you add 0.96 pints of oil to 6 gallons of gas.<BR>\n" );
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document.write( "Hope this helps you to understand the problem and how it can be solved by using a proportion.<BR>\n" );
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