document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1174194>Question 1174194</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Situation: Lovely paid Php 600 for 10 kilos of rice and 3 kilos of fish.\r<BR>\n" );
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document.write( "a. What mathematical inequality represents the total amount Lovely paid? Define the variables used.<BR>\n" );
document.write( "b. Suppose a kilo of rice costs Php 35. What could be the greatest cost of a kilo of fish to the nearest pesos? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #802225 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=802225\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a) r = price of 1 kilo of rice<BR>\n" );
document.write( "f = price of 1 kilo of fish\r<BR>\n" );
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document.write( "10r + 3f <= 600\r<BR>\n" );
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document.write( "b) r = 35, so plug that in:\r<BR>\n" );
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document.write( "10(35) + 3f <= 600<BR>\n" );
document.write( "350 + 3f <= 600<BR>\n" );
document.write( "3f <= 250\r<BR>\n" );
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document.write( "f <= 250/3 or f <= 83 (rounded down to the nearest peso) </SPAN>\n" );
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