document.write( "Question 110005: find the length of a radius of the circle x^2+y^2-4x-6y-5=0 \n" ); document.write( "

Algebra.Com's Answer #80218 by elima(1433) $\"\"$ $\"About$

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find the length of a radius of the cirle x^2+y^2-4x-6y-5=0
\n" ); document.write( "We need to get this equation in the circle form;
\n" ); document.write( "Lets first out the x's and y's together and move the 5 to other side;
\n" ); document.write( " $\"x%5E2-4x%2By%5E2-6y=5\"$
\n" ); document.write( "Now we want to complete the square for each, x's and y's, then factor;
\n" ); document.write( " $\"x%5E2-4x%2B4%2By%5E2-6y%2B9=5%2B4%2B9\"$
\n" ); document.write( " $\"%28x-2%29%5E2%2B%28x-3%29%5E2=18\"$
\n" ); document.write( "Now we have the radius= $\"sqrt%2818%29\"$
\n" ); document.write( ":) \n" ); document.write( "

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