document.write( "Question 1176084: In 11.4 days a certain amount of iodine - 131 has decayed to (1/√2) of its original amount. What is the half-life of iodine - 131? \n" ); document.write( "
Algebra.Com's Answer #802114 by ikleyn(52803)\"\" \"About 
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document.write( "Notice that  \"%281%2Fsqrt%282%29%29%2A%281%2Fsqrt%282%29%29\" = \"1%2F2\".\r\n" );
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document.write( "It means that half-life of iodine-131 is two times 11.4 days,  or  2*11.4 = 22.8 days.    ANSWER\r\n" );
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\n" ); document.write( "\n" ); document.write( "To learn more on the subject,  look into the lesson\r
\n" ); document.write( "\n" ); document.write( "    - Radioactive decay problems \r
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\n" ); document.write( "\n" ); document.write( "Also,  you have this free of charge online textbook in ALGEBRA-I in this site\r
\n" ); document.write( "\n" ); document.write( "    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.\r
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\n" ); document.write( "\n" ); document.write( "The referred lesson is the part of this online textbook under the topic \"Logarithms\".\r
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\n" ); document.write( "\n" ); document.write( "Save the link to this online textbook together with its description\r
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\n" ); document.write( "\n" ); document.write( "Free of charge online textbook in ALGEBRA-I
\n" ); document.write( "https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson\r
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\n" ); document.write( "\n" ); document.write( "to your archive and use it when it is needed.\r
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\n" ); document.write( "\n" ); document.write( "By the way,  the  Internet sources give  ANOTHER  value for the  Iodine-131  half-life:   8 days.\r
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\n" ); document.write( "\n" ); document.write( "So,  your input data is  INCORRECT.\r
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\n" ); document.write( "\n" ); document.write( "See,  for example,  these sources\r
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\n" ); document.write( "\n" ); document.write( "https://en.wikipedia.org/wiki/Iodine-131\r
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\n" ); document.write( "\n" ); document.write( "https://www.radioactivity.eu.com/site/pages/Iodine_131.htm\r
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