document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=948046>Question 948046</A>: <I><SPAN STYLE=\"word-break: break-all;\"> write the expression in the standard form a+bi: 2i^15-i^7. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #802101 by </B><A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><B>CubeyThePenguin(3113)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CubeyThePenguin><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CubeyThePenguin><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=802101\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Patterns of powers of i:\r<BR>\n" );
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document.write( "i^0 = 1<BR>\n" );
document.write( "i^1 = i<BR>\n" );
document.write( "i^2 = -1<BR>\n" );
document.write( "i^3 = -i\r<BR>\n" );
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document.write( "2i^15 - i^7 = 2(-i) - i = -3i </SPAN>\n" );
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