document.write( "Question 110068: a man rode a bycycle for 12 miles then hiked an additional 8 miles . the total time for the trip was 5 hrs . if the rate when he was riding his bicycle was 10 miles per hour faster than his rate walking , what was each rate \n" ); document.write( "
Algebra.Com's Answer #80201 by stanbon(75887)\"\" \"About 
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a man rode a bycycle for 12 miles then hiked an additional 8 miles . the total time for the trip was 5 hrs . if the rate when he was riding his bicycle was 10 miles per hour faster than his rate walking , what was each rate
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\n" ); document.write( "Bike DATA:
\n" ); document.write( "distance = 12 miles ; rate= x mph ; time = d/r = 12/x hrs
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\n" ); document.write( "Walk DATA:
\n" ); document.write( "distance = 8 miles ; rate = x-10 mph ; time = d/r = 8/(x-10) hrs
\n" ); document.write( "--------------------
\n" ); document.write( "EQUATION:
\n" ); document.write( "time + time = 5 hrs.
\n" ); document.write( "12/x + 8/(x-10) = 5
\n" ); document.write( "3/x + 2/(x-10) = 5/4
\n" ); document.write( "[3x-30+2x] = (5/4)x(x-10)
\n" ); document.write( "5x-30 = (5/4)x(x-10)
\n" ); document.write( "x-6 = [x^2-10x)/4
\n" ); document.write( "x^2-10x = 4x-24
\n" ); document.write( "x^2-14x+24=0
\n" ); document.write( "x^2-2x-12x+24=0
\n" ); document.write( "x(x-2)-12(x-2)=0
\n" ); document.write( "(x-2)(x-12)=0
\n" ); document.write( "x = 2 or x = 12
\n" ); document.write( "Positive answer:
\n" ); document.write( "x-10 = 2 mph (walking rate)
\n" ); document.write( "x=12 mph (biking rate)\r
\n" ); document.write( "\n" ); document.write( "==================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
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