document.write( "Question 1176057: A hot bar of iron at 1100 degrees Fahrenheit is quenched in oil at 350 degrees. After 2 minutes, the temperature of the iron is 750 degrees.\r
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document.write( "(a) Find the value for k in Newton's Law of Cooling. Round your answer to the nearest thousandth.\r
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document.write( "k = ?\r
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document.write( "(b) What will the temperature of the iron be after 10 minutes? Round your answer to the nearest degree.\r
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document.write( "? degrees Fahrenheit\r
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document.write( "(c) How long will it take for the iron to reach 400 degrees? Round your answer to the nearest tenth of a minute.\r
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document.write( "? minutes \n" );
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Algebra.Com's Answer #801973 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \r\n" ); document.write( "Hi\r\n" ); document.write( "After 2 minutes, the temperature of the iron is 750 degrees.\r\n" ); document.write( "T(t)=Ae^kt + Ts\r\n" ); document.write( "t is time\r\n" ); document.write( "•A is the difference between the initial temperature of the object and the surroundings (1100-350)\r\n" ); document.write( "•k is a constant, the continuous rate of cooling of the object\r\n" ); document.write( "T(2) = 750\r\n" ); document.write( "750=750e^2k + 350\r\n" ); document.write( "400 = 750e^2k\r\n" ); document.write( "ln(400/750)/2 = k = -.314\r\n" ); document.write( "\r\n" ); document.write( "(b) What will the temperature of the iron be after 10 minutes? \r\n" ); document.write( "T=750e^-3.14 + 350 = 382degrees\r\n" ); document.write( "\r\n" ); document.write( "(c) How long will it take for the iron to reach 400 degrees?\r\n" ); document.write( "400=750e^(-.314)t + 350\r\n" ); document.write( " ln(50/750)/-.314 = t = 8.6 min \r\n" ); document.write( "\r\n" ); document.write( "Wish You the Best in your Studies.\r\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |