document.write( "Question 1176010: Peter travels from his place to his uncle house a distance of 30km.He cycles for two thirds of the journey before walking for the rest of the journey. If his cycling speed is 10km/hr more than the walking speed and the whole journey took him 3hrs 20 minutes, calculate his cycling speed. \n" ); document.write( "
Algebra.Com's Answer #801885 by ikleyn(52779)\"\" \"About 
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\n" ); document.write( "Peter travels from his place to his uncle house a distance of 30km.He cycles for two thirds of the journey
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document.write( "Let x be his cycling speed in km/h;  then his walking speed was (x-10) km/h.\r\n" );
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document.write( "He cycled 20 km at the speed x km/h --- hence, he spent  \"20%2Fx\"  hours for this part of the journey.\r\n" );
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document.write( "He walked 10 km at the speed (x-10) km/h --- hence, he spent  \"10%2F%28x-10%29\"  hours for this part of the journey.\r\n" );
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document.write( "The total time was  3 hours 20 minutes = 3 \"1%2F3\" hours = \"10%2F3\" hours.\r\n" );
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document.write( "It gives you this \"time equation\"\r\n" );
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document.write( "    \"20%2Fx\" + \"10%2F%28x-10%29\" = \"10%2F3\".     (1)\r\n" );
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document.write( "To solve it, multiply both sides by 3\r\n" );
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document.write( "    \"60%2Fx\" + \"30%2F%28x-10%29\" = 10.            (2)\r\n" );
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document.write( "At this point, you just can easily guess the solution MENTALLY:  it is x= 15 km/h.\r\n" );
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document.write( "Alternatively, you may reduce equation (1) or (2) to the standard form quadratic equation and solve it formally.\r\n" );
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document.write( "ANSWER.  His cycling speed is 15 km/h.\r\n" );
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document.write( "CHECK.  I will check equation (1) :  \"20%2F15+%2B+10%2F5\" = 1 \"1%2F3\" + 2 = 3 + \"1%2F3\"  hours.    ! Correct !\r\n" );
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